$\left\{ \begin{array} { c }
x - y + 3 z = - 8 \
2 x + z = 0 \
x + 5 y + z = 40
\end{array} \right.$
A) x=0, y=8, z=0
B) x=0, y=-8, z=-8
C) x=8, y=8, z=0
D) x=-8, y=0, z=0

Question

$\left\{ \begin{array} { c } 
x - y + 3 z = - 8 \
2 x + z = 0 \
x + 5 y + z = 40
\end{array} \right.$
A)  x=0, y=8, z=0 
B)  x=0, y=-8, z=-8 
C)  x=8, y=8, z=0 
D)  x=-8, y=0, z=0

Quizplus · Accepted Answer

Solving the system of equations simultaneously, we can substitute the second equation into the others to find values for x, y, and z. The correct solution is x=0, y=8, z=0, which matches option A.

{x−y+3z=−82x+z=0x+5y+z=40\left\{ \begin{array} { c } x - y + 3 z = - 8 \\2 x + z = 0 \\x + 5 y + z = 40\end{array} \right.⎩⎨⎧​x−y+3z=−82x+z=0x+5y+z=40​

$\left\{ \begin{array} { c } x - y + 3 z = - 8 \\2 x + z = 0 \\x + 5 y + z = 40\end{array} \right.$