Solve the problem.
-A newspaper carrier has $12.80 in change. He has two more quarters than dimes but three times as many nickels as quarters. How many coins of each type does he have?
A) 78 quarters, 76 dimes, 26 nickels
B) 26 quarters, 24 dimes, 78 nickels
C) 26 quarters, 28 dimes, 78 nickels
D) 28 quarters, 26 dimes, 84 nickels

Question

Quizplus · Accepted Answer

The correct answer is found by setting up equations based on the given information. Let the number of dimes be $d$, quarters $q$, and nickels $n$. We have $q = d + 2$ and $n = 3q$. The total amount in dollars is given by $0.10d + 0.25q + 0.05n = 12.80$. Substituting the relationships between the coins into the equation and solving gives us 26 quarters, 24 dimes, and 78 nickels.

Solve the Problem. -A Newspaper Carrier Has $12.80 in Change. He Has Two