Solve the problem.
-The radiator in a certain make of car needs to contain 40 liters of 40% antifreeze. The radiator now contains 40 liters of 20% antifreeze. How many liters of this solution must be drained and replaced with 100% antifreeze
To get the desired strength?
A) 10.0 liters
B) 20 liters
C) 13.3 liters
D) 16 liters

Question

Quizplus · Accepted Answer

To achieve a 40% antifreeze solution in a 40-liter mixture, you need 40 * 0.4 = 16 liters of pure antifreeze. The current mixture has 40 * 0.2 = 8 liters of antifreeze. To increase the antifreeze content from 8 liters to 16 liters, you need to add 16 - 8 = 8 liters of pure antifreeze. If you remove x liters of the current mixture, you also remove 0.2x liters of antifreeze. To keep the total volume at 40 liters, you replace x liters of the mixture with x liters of pure antifreeze, which adds x liters of antifreeze. The equation to solve is 8 - 0.2x + x = 16, simplifying to 0.8x = 8, giving x = 10.

Solve the Problem. -The Radiator in a Certain Make of Car Needs to Car