Factor completely using the trial and error method to factor trinomials. If unfactorable, indicate that the polynomial is
prime.
-$x ^ { 6 } - 3 x ^ { 5 } - 18 x ^ { 4 }$
A) $x ^ { 4 } ( x + 3 ) ( x + 6 )$
B) $x ^ { 3 } \left( x ^ { 2 } - 3 x - 18 \right)$
C) $x ^ { 4 } ( x - 3 ) ( x - 6 )$
D) $x ^ { 4 } ( x + 3 ) ( x - 6 )$

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The Answer of Factor completely using the trial and error method to factor trinomials. If unfactorable, indicate that the polynomial is
prime.
-$x ^ { 6 } - 3 x ^ { 5 } - 18 x ^ { 4 }$
A) $x ^ { 4 } ( x + 3 ) ( x + 6 )$
B) $x ^ { 3 } \left( x ^ { 2 } - 3 x - 18 \right)$
C) $x ^ { 4 } ( x - 3 ) ( x - 6 )$
D) $x ^ { 4 } ( x + 3 ) ( x - 6 )$

Factor Completely Using the Trial and Error Method to Factor x6−3x5−18x4x ^ { 6 } - 3 x ^ { 5 } - 18 x ^ { 4 }x6−3x5−18x4

Factor Completely Using the Trial and Error Method to Factor $x ^ { 6 } - 3 x ^ { 5 } - 18 x ^ { 4 }$