Perform the indicated operation(s). Simplify if possible.
-$$\frac { 8 y ^ { 2 } + 3 } { 6 y ^ { 2 } + 7 y + 1 } - \frac { 2 - 8 y } { 6 y ^ { 2 } + 7 y + 1 } - \frac { 3 y ^ { 2 } + 2 y } { 6 y ^ { 2 } + 7 y + 1 }$$
A) $\frac { y + 1 } { 6 y + 1 }$
B) $\frac { 5 y + 1 } { y + 1 }$
C) $\frac { 5 y - 1 } { 6 y + 1 }$
D) $\frac { 5 y + 1 } { 6 y + 1 }$

Question

Quizplus · Accepted Answer

Since all fractions have the same denominator, you can combine the numerators directly: $8y^2 + 3 - (2 - 8y) - (3y^2 + 2y) = 5y^2 + 8y + 1$. Simplifying the denominator doesn't change it, so the fraction becomes $\frac{5y^2 + 8y + 1}{6y^2 + 7y + 1}$. Factoring the numerator as $(5y + 1)(y + 1)$ and the denominator as $(6y + 1)(y + 1)$, and then simplifying, gives $\frac{5y + 1}{6y + 1}$.

Perform the Indicated Operation(s) A) y+16y+1\frac { y + 1 } { 6 y + 1 }6y+1y+1​

Perform the Indicated Operation(s) A) $\frac { y + 1 } { 6 y + 1 }$