Find the probability.
-A child rolls a 6-sided die 6 times. What is the probability of the child rolling no more than three Twos? Round to the nearest ten-thousandth.
A) 0.3812
B) 0.6774
C) 0.9913
D) 0.9649

Question

Find the probability.
-A child rolls a 6-sided die 6 times. What is the probability of the child rolling no more than three Twos? Round to the nearest ten-thousandth.
A) 0.3812
B) 0.6774
C) 0.9913
D) 0.9649

Quizplus · Accepted Answer

The probability of rolling no more than three Twos in six rolls of a 6-sided die can be calculated using the binomial probability formula. The probability of rolling a Two (success) is $ \frac{1}{6} $ and not rolling a Two (failure) is $ \frac{5}{6} $. We calculate the probability for 0, 1, 2, and 3 successes (rolling a Two) and sum these probabilities. The calculations for each of these scenarios involve combinations and the probabilities of successes and failures raised to the appropriate powers. The sum of these probabilities gives the total probability of rolling no more than three Twos, which is approximately 0.9913, making option C the correct answer.

Find the Probability. -A Child Rolls a 6-Sided Die 6 Times. What Is