The table below represents a random sample of the number of deaths per 100 cases for a certain illness overtime. If a person infected with this illness is randomly selected from all infected people, find the probabilitythat the person lives 3-4 years after diagnosis. Express your answer as a simplified fraction and as a decimal. $\begin{array}{l|l}
\text { Years after Diagnosis } & \text { Number deaths } \
\hline 1-2 & 15 \
3-4 & 35 \
5-6 & 16 \
7-8 & 9 \
9-10 & 6 \
11-12 & 4 \
13-14 & 2 \
15+ & 13
\end{array}$
A) $\frac { 35 } { 100 } ; 0.35$
B) $\frac { 1 } { 35 } ; 0.029$
C) $\frac { 35 } { 65 } ; 0.538$
D) $\frac { 7 } { 120 } ; 0.058$

Question

Quizplus · Accepted Answer

The total number of cases is the sum of deaths in all time periods, which is $15 + 35 + 16 + 9 + 6 + 4 + 2 + 13 = 100$. The number of deaths in the 3-4 year period is 35. Therefore, the probability is $\frac{35}{100} = 0.35$.

The Table Below Represents a Random Sample of the Number