A seed company has a test plot in which it is testing the germination of a hybrid seed. They plant 50 rows of 40seeds per row. After a two-week period, the researchers count how many seed per row have sprouted. Theynoted that least number of seeds to germinate was 33 and some rows had all 40 germinate. The germinationdata is given below in the table. The random variable x represents the number of seed in a row thatgerminated and P(x) represents the probability of selecting a row with that number of seed germinating.Determine the mean number of seeds per row that germinated. $$\begin{array} { | c | c | c | c | c | c | c | c | c | }
\hline x & 33 & 34 & 35 & 36 & 37 & 38 & 39 & 40 \
\hline P ( x ) & 0.02 & 0.06 & 0.10 & 0.20 & 0.24 & 0.26 & 0.10 & 0.02 \
\hline
\end{array}$$
A) 36.9
B) 36.5
C) 36
D) 0.13

Question

A seed company has a test plot in which it is testing the germination of a hybrid seed. They plant 50 rows of 40seeds per row. After a two-week period, the researchers count how many seed per row have sprouted. Theynoted that least number of seeds to germinate was 33 and some rows had all 40 germinate. The germinationdata is given below in the table. The random variable x represents the number of seed in a row thatgerminated and P(x) represents the probability of selecting a row with that number of seed germinating.Determine the mean number of seeds per row that germinated. $$\begin{array} { | c | c | c | c | c | c | c | c | c | } 
\hline x & 33 & 34 & 35 & 36 & 37 & 38 & 39 & 40 \
\hline P ( x ) & 0.02 & 0.06 & 0.10 & 0.20 & 0.24 & 0.26 & 0.10 & 0.02 \
\hline
\end{array}$$
A) 36.9
B) 36.5
C) 36
D) 0.13

Quizplus · Accepted Answer

To find the mean number of seeds per row that germinated, multiply each value of $x$ by its corresponding probability $P(x)$ and sum these products: $$Mean = \sum (x \cdot P(x)) = (33 \cdot 0.02) + (34 \cdot 0.06) + (35 \cdot 0.10) + (36 \cdot 0.20) + (37 \cdot 0.24) + (38 \cdot 0.26) + (39 \cdot 0.10) + (40 \cdot 0.02) = 36.9.$$

A Seed Company Has a Test Plot in Which It