Let t0 be a specific value of t. Find t0 such that the statement is true: $\mathrm { P } \left( \mathrm { t } \geq \mathrm { t } _ { 0 } \right) = 0.005 \text { where } \mathrm { df } = 20$
A) 2.845
B) -2.845
C) 2.861
D) -2.861

Question

Quizplus · Accepted Answer

Given a probability of 0.005 in the right tail of a t-distribution with 20 degrees of freedom, we look for the t-value that corresponds to this probability. The positive t-value (2.845) is correct because probabilities in the context of t-distributions are typically looked up for the right tail, and the question specifies $P(t \geq t_0) = 0.005$, indicating a right-tail scenario.

Let T0 Be a Specific Value of T P(t≥t0)=0.005 where df=20\mathrm { P } \left( \mathrm { t } \geq \mathrm { t } _ { 0 } \right) = 0.005 \text { where } \mathrm { df } = 20P(t≥t0​)=0.005 where df=20

Let T0 Be a Specific Value of T $\mathrm { P } \left( \mathrm { t } \geq \mathrm { t } _ { 0 } \right) = 0.005 \text { where } \mathrm { df } = 20$