Factor completely.
-$3 c ^ { 9 / 5 } - 3 c ^ { 4 / 5 }$
A) $3 c ^ { 9 / 5 } ( c - 1 )$
B) $\frac { 3 ( c - 1 ) } { c^{4 / 5} }$
C) $3 c ^ { 4 / 5 } ( c - 1 )$
D) $c ^ { 4 / 5 } ( 3 c - 3 )$

Question

Quizplus · Accepted Answer

The correct factorization is found by taking out the common factor of $3c^{4/5}$ from both terms, leaving $3c^{4/5}(c^{5/5}-1)$, which simplifies to $3c^{4/5}(c-1)$.

Factor Completely 3c9/5−3c4/53 c ^ { 9 / 5 } - 3 c ^ { 4 / 5 }3c9/5−3c4/5

Factor Completely $3 c ^ { 9 / 5 } - 3 c ^ { 4 / 5 }$