Write the domain of the function in interval notation.
-$$h ( a ) = \sqrt { 64 - a ^ { 2 } }$$
A) $[ - 8,8 ]$
B) $[ 8 , \infty )$
C) $( - \infty , - 8 ] \cup [ 8 , \infty )$
D) $( - 8,8 )$

Question

Quizplus · Accepted Answer

The domain of the function $h(a) = \sqrt{64 - a^2}$ consists of all values of $a$ for which the expression under the square root, $64 - a^2$, is greater than or equal to 0. This occurs when $a^2 \leq 64$, which simplifies to $-8 \leq a \leq 8$. Therefore, the domain in interval notation is $[ - 8,8 ]$.

Write the Domain of the Function in Interval Notation h(a)=64−a2h ( a ) = \sqrt { 64 - a ^ { 2 } }h(a)=64−a2​

Write the Domain of the Function in Interval Notation $h ( a ) = \sqrt { 64 - a ^ { 2 } }$