Solve the inequality. Write the solution set in interval notation.
-$\frac { x ^ { 2 } } { x ^ { 2 } + 25 } \geq 0$
A) $( - \infty , \infty )$
B) $( - \infty , 5 ] \cup [ 5 , \infty )$
C) $\{ 0 \}$
D) $( - \infty , 0 ) \cup ( 0 , \infty )$

Question

Quizplus · Accepted Answer

The denominator $x^2 + 25$ is always positive for all real x, and the numerator $x^2$ is non-negative. Thus, the fraction is non-negative for all x, making the solution set all real numbers, $( - \infty , \infty )$.

Solve the Inequality x2x2+25≥0\frac { x ^ { 2 } } { x ^ { 2 } + 25 } \geq 0x2+25x2​≥0

Solve the Inequality $\frac { x ^ { 2 } } { x ^ { 2 } + 25 } \geq 0$