Solve the inequality. Write the solution set in interval notation.
-$$\frac { 3 x - 4 } { 3 + 2 x }

Question

Solve the inequality. Write the solution set in interval notation.
-$$\frac { 3 x - 4 } { 3 + 2 x } < 0$$
A) $\left( - \infty , - \frac { 3 } { 2 } \right) \cup \left( \frac { 4 } { 3 } , \frac { 3 } { 2 } \right)$
B) $\left( - \frac { 3 } { 2 } , \frac { 4 } { 3 } \right)$
C) $\left( - \infty , - \frac { 4 } { 3 } \right) \cup \left( \frac { 3 } { 2 } , \infty \right)$
D) $\left( - \frac { 4 } { 3 } , \frac { 3 } { 2 } \right)$

Quizplus · Accepted Answer

The Answer of Solve the inequality. Write the solution set in interval notation.
-$$\frac { 3 x - 4 } { 3 + 2 x } < 0$$
A) $\left( - \infty , - \frac { 3 } { 2 } \right) \cup \left( \frac { 4 } { 3 } , \frac { 3 } { 2 } \right)$
B) $\left( - \frac { 3 } { 2 } , \frac { 4 } { 3 } \right)$
C) $\left( - \infty , - \frac { 4 } { 3 } \right) \cup \left( \frac { 3 } { 2 } , \infty \right)$
D) $\left( - \frac { 4 } { 3 } , \frac { 3 } { 2 } \right)$

Solve the Inequality 3x−43+2x<0\frac { 3 x - 4 } { 3 + 2 x } < 03+2x3x−4​<0

Solve the Inequality $\frac { 3 x - 4 } { 3 + 2 x } < 0$