Identify the asymptotes.
-$f ( x ) = \frac { - 2 x ^ { 2 } + 5 x - 4 } { x + 3 }$
A) Vertical asymptote: $x = - 3$
B) Horizontal asymptote: $x = 0$
Vertical asymptote: $x = 3$
C) Vertical asymptote: $x = - 3$
Slant asymptote: $y = - 2 x + 11$
D) Horizontal asymptote: $x = 0$
Slant asymptote: $y = - 2 x + 11$

Question

Quizplus · Accepted Answer

The vertical asymptote occurs where the denominator is zero, which is at $x = -3$. Since the degree of the numerator is one more than the degree of the denominator, there is a slant (oblique) asymptote, which can be found by dividing the numerator by the denominator. The division yields $y = -2x + 11$ as the slant asymptote.

Identify the Asymptotes f(x)=−2x2+5x−4x+3f ( x ) = \frac { - 2 x ^ { 2 } + 5 x - 4 } { x + 3 }f(x)=x+3−2x2+5x−4​

Identify the Asymptotes $f ( x ) = \frac { - 2 x ^ { 2 } + 5 x - 4 } { x + 3 }$