Use the factor theorem to factor the polynomial.
-Factor $f ( x ) = 6 x ^ { 3 } + 31 x ^ { 2 } - 29 x + 6$ given that $\frac { 1 } { 3 }$ is a zero.
A) $f ( x ) = ( 3 x - 1 ) ( 2 x + 1 ) ( x - 6 )$
B) $f ( x ) = ( 3 x + 1 ) ( 2 x - 1 ) ( x - 6 )$
C) $f ( x ) = ( 3 x - 1 ) ( 2 x - 1 ) ( x + 6 )$
D) $f ( x ) = ( 3 x + 1 ) ( 2 x + 1 ) ( x + 6 )$

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The Answer of Use the factor theorem to factor the polynomial.
-Factor $f ( x ) = 6 x ^ { 3 } + 31 x ^ { 2 } - 29 x + 6$ given that $\frac { 1 } { 3 }$ is a zero.
A) $f ( x ) = ( 3 x - 1 ) ( 2 x + 1 ) ( x - 6 )$
B) $f ( x ) = ( 3 x + 1 ) ( 2 x - 1 ) ( x - 6 )$
C) $f ( x ) = ( 3 x - 1 ) ( 2 x - 1 ) ( x + 6 )$
D) $f ( x ) = ( 3 x + 1 ) ( 2 x + 1 ) ( x + 6 )$

Use the Factor Theorem to Factor the Polynomial f(x)=6x3+31x2−29x+6f ( x ) = 6 x ^ { 3 } + 31 x ^ { 2 } - 29 x + 6f(x)=6x3+31x2−29x+6

Use the Factor Theorem to Factor the Polynomial $f ( x ) = 6 x ^ { 3 } + 31 x ^ { 2 } - 29 x + 6$