Find the vertex of the parabola by applying the vertex formula.
-$$P ( x ) = 1.4 x ^ { 2 } + 1.3 x - 5.1$$
A) $( - 0.46 , - 5.402 )$
B) $( - 0.46 , - 5.994 )$
C) $( 0.46 , - 4.206 )$
D) $( 0.46,5.994 )$

Question

Quizplus · Accepted Answer

The vertex of a parabola given by $P(x) = ax^2 + bx + c$ can be found using the formula $(- \frac{b}{2a}, P(- \frac{b}{2a}))$. Here, $a = 1.4$, $b = 1.3$, and $c = -5.1$. Thus, the x-coordinate of the vertex is $- \frac{1.3}{2 \cdot 1.4} = -0.4642857$, approximately $-0.46$. Substituting $-0.46$ for $x$ in $P(x)$ gives the y-coordinate, which is approximately $-5.402$, making the vertex $(-0.46, -5.402)$.

Find the Vertex of the Parabola by Applying the Vertex P(x)=1.4x2+1.3x−5.1P ( x ) = 1.4 x ^ { 2 } + 1.3 x - 5.1P(x)=1.4x2+1.3x−5.1

Find the Vertex of the Parabola by Applying the Vertex $P ( x ) = 1.4 x ^ { 2 } + 1.3 x - 5.1$