Solve the equation.
-$\frac { 10 ^ { x } - 31 \cdot 10 ^ { - x } } { 5 } = 6$
A) $\{ 31 , - 1 \}$
B) { }
C) $\{ \log 31 \} ; \mathrm { x } \approx 1.4914$
D) $\{ 31 \}$

Question

Solve the equation.
-$\frac { 10 ^ { x } - 31 \cdot 10 ^ { - x } } { 5 } = 6$
A) $\{ 31 , - 1 \}$
B) {  }
C) $\{ \log 31 \} ; \mathrm { x } \approx 1.4914$
D) $\{ 31 \}$

Quizplus · Accepted Answer

The equation can be solved by multiplying both sides by 5 and then rearranging it into a quadratic equation in terms of $10^x$. Solving the quadratic equation yields the solution $x = \log 31$, which is approximately 1.4914.

Solve the Equation 10x−31⋅10−x5=6\frac { 10 ^ { x } - 31 \cdot 10 ^ { - x } } { 5 } = 6510x−31⋅10−x​=6

Solve the Equation $\frac { 10 ^ { x } - 31 \cdot 10 ^ { - x } } { 5 } = 6$