Solve the Problem $L = 10 \log \left( \frac { I } { I _ { 0 } } \right)$

Solve the problem.
-The formula $L = 10 \log \left( \frac { I } { I _ { 0 } } \right)$ gives the loudness of sound $L$ (in $\mathrm { dB }$ ) based on the intensity of the sound (in $\mathrm { W } / \mathrm { m } ^ { 2 }$ ) . The value $I _ { 0 } = 10 ^ { - 12 } \mathrm {~W} / \mathrm { m } ^ { 2 }$ is the minimal threshold for hearing for mid-frequency sounds. Hearing impairment is often measured according to the minimal sound level (in $\mathrm { dB }$ ) detected by an individual for sounds of various frequencies. If the minimum loudness of sound detected by an individual is $60 \mathrm {~dB}$ , determine the corresponding intensity of sound.

A) $10 ^ { - 0.5 } \mathrm {~W} / \mathrm { m } ^ { 2 }$
B) $10 ^ { 0.5 } \mathrm {~W} / \mathrm { m } ^ { 2 }$
C) $10 ^ { 6 } \mathrm {~W} / \mathrm { m } ^ { 2 }$
D) $10 ^ { - 6 } \mathrm {~W} / \mathrm { m } ^ { 2 }$