Write the logarithm as a sum or difference of logarithms. Simplify each term as much as possible.
-$\log _ { 8 } \sqrt [ 3 ] { y _ { \sqrt { 8 } } }$
A) $\frac { 1 } { 3 } \log _ { 8 } y + \frac { 1 } { 2 }$
B) $\frac { 1 } { 3 } \log _ { 8 } y - \frac { 1 } { 6 }$
C) $\frac { 1 } { 3 } \log _ { 8 } y - \frac { 1 } { 2 }$
D) $\frac { 1 } { 3 } \log _ { 8 } y + \frac { 1 } { 6 }$

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The Answer of Write the logarithm as a sum or difference of logarithms. Simplify each term as much as possible.
-$\log _ { 8 } \sqrt [ 3 ] { y _ { \sqrt { 8 } } }$
A) $\frac { 1 } { 3 } \log _ { 8 } y + \frac { 1 } { 2 }$
B) $\frac { 1 } { 3 } \log _ { 8 } y - \frac { 1 } { 6 }$
C) $\frac { 1 } { 3 } \log _ { 8 } y - \frac { 1 } { 2 }$
D) $\frac { 1 } { 3 } \log _ { 8 } y + \frac { 1 } { 6 }$

Write the Logarithm as a Sum or Difference of Logarithms log⁡8y83\log _ { 8 } \sqrt [ 3 ] { y _ { \sqrt { 8 } } }log8​3y8​​​

Write the Logarithm as a Sum or Difference of Logarithms $\log _ { 8 } \sqrt [ 3 ] { y _ { \sqrt { 8 } } }$