Approximate $f ( x ) = \ln x$ for the given value of x. Round to four decimal places.
-$f ( \sqrt { 229 } )$
A) 1.5133
B) 2.7169
C) 2.5133
D) 1.1799

Question

Quizplus · Accepted Answer

The value of $f(\sqrt{229}) = \ln(\sqrt{229})$. First, find the square root of 229, which is approximately 15.1327. Then, take the natural logarithm of this value, which gives approximately 2.7169 when rounded to four decimal places.

Approximate f(x)=ln⁡xf ( x ) = \ln xf(x)=lnx For the Given Value of X

Approximate $f ( x ) = \ln x$ For the Given Value of X