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Solve the Problem T(t)T ( t ) Is Modeled By T(t)=Ta+(T0Ta)ektT ( t ) = T _ { a } + \left( T _ { 0 } - T _ { a } \right) e ^ { - k t }

Question 80

Multiple Choice

Solve the problem.
-Newton's law of cooling indicates that the temperature of a warm object will decrease exponentially with time and will approach the temperature of the surrounding air. The temperature T(t) T ( t ) is modeled by T(t) =Ta+(T0Ta) ektT ( t ) = T _ { a } + \left( T _ { 0 } - T _ { a } \right) e ^ { - k t } . In this model, TaT _ { a } represents the temperature of the surrounding air, T0T _ { 0 } represents the initial temperature of the object and tt is the time after the object starts cooling. The value of kk is the cooling rate and is a constant related to the physical properties of the object.
Water in a water heater is originally 131F131 ^ { \circ } \mathrm { F } . The water heater is shut off and the water cools to the temperature of the surrounding air, which is 80F80 ^ { \circ } \mathrm { F } . The water cools slowly because of the insulation inside the heater, and the rate of cooling is 0.003480.00348 . Dominic does not like to shower with water less than 116F116 ^ { \circ } \mathrm { F } . If Dominic waits 24hr24 \mathrm { hr } after the heater is shut off, will the water still be warm enough for a shower? How warm will the water be?


A) No; the temperature after 24hr24 \mathrm { hr } will be approximately 80F80 ^ { \circ } \mathrm { F }
B) Yes; the temperature after 24hr24 \mathrm { hr } will be approximately 128F128 ^ { \circ } \mathrm { F }
C) Yes; the temperature after 24hr24 \mathrm { hr } will be approximately 127F127 ^ { \circ } \mathrm { F }
D) No\mathrm { No } ; the temperature after 24hr24 \mathrm { hr } will be approximately 106F106 ^ { \circ } \mathrm { F }

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