Solve the system by substitution.
-$$\begin{aligned}
x + 4 y & = 6 \
3 x - 5 y & = - 16
\end{aligned}$$
A) $\{ ( 2,1 ) \}$
B) $\{ ( 6,0 ) \}$
C) $\{ ( 10 , - 1 ) \}$
D) $\{ ( - 2,2 ) \}$

Question

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The Answer of Solve the system by substitution.
-$$\begin{aligned}
x + 4 y & = 6 \
3 x - 5 y & = - 16
\end{aligned}$$
A) $\{ ( 2,1 ) \}$
B) $\{ ( 6,0 ) \}$
C) $\{ ( 10 , - 1 ) \}$
D) $\{ ( - 2,2 ) \}$

Solve the System by Substitution x+4y=63x−5y=−16\begin{aligned}x + 4 y & = 6 \\3 x - 5 y & = - 16\end{aligned}x+4y3x−5y​=6=−16​

Solve the System by Substitution $\begin{aligned}x + 4 y & = 6 \\3 x - 5 y & = - 16\end{aligned}$