Solve the Problem $A = \left[ \begin{array} { r r r } - 1 & 1 & 3 \\ 1 & 5 & 1 \end{array} \right]$

Solve the problem.
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a. Write a matrix A that represents the coordinates of the triangle. Place the x-coordinate of each point in the first row of A and the corresponding y-coordinate in the second row of A.
b. Use addition of matrices to shift the triangle 5 units to the right and 4 units down.

A) a. $A = \left[ \begin{array} { r r r } - 1 & 1 & 3 \\ 1 & 5 & 1 \end{array} \right]$
b. $\left[ \begin{array} { r r r } 4 & 6 & 8 \\ - 3 & 1 & - 3 \end{array} \right]$

B) a. $A = \left[ \begin{array} { r r r } - 1 & 1 & 3 \\ 1 & 5 & 1 \end{array} \right]$
b. $\left[ \begin{array} { c c c } 4 & 6 & 8 \\ 5 & 9 & 5 \end{array} \right]$

C) a. $A = \left[ \begin{array} { c c c } 1 & 5 & 1 \\ - 1 & 1 & 3 \end{array} \right]$
b. $\left[ \begin{array} { r r r } - 3 & 1 & - 3 \\ 4 & 6 & 8 \end{array} \right]$

D) a. $A = \left[ \begin{array} { r r r } - 1 & 1 & 3 \\ 1 & 5 & 1 \end{array} \right]$
b. $\left[ \begin{array} { r r r } - 6 & - 4 & - 2 \\ 5 & 9 & 5 \end{array} \right]$