Solve the system using Gaussian elimination or Gauss-Jordan elimination.
-$$\begin{array} { l }
- 6 x + 15 y = 15 \
2 x - 5 y = - 5
\end{array}$$
A) $\{ ( 15 , - 5 ) \}$
B) $\left\{ \left( \frac { 5 } { 2 } x - \frac { 5 } { 2 } , y \right) \mid y \right.$ is any real number
C) $\{ ( - 9 , - 5 ) \}$
D){}

Question

Solve the system using Gaussian elimination or Gauss-Jordan elimination.
-$$\begin{array} { l } 
- 6 x + 15 y = 15 \
2 x - 5 y = - 5
\end{array}$$
A) $\{ ( 15 , - 5 ) \}$
B) $\left\{ \left( \frac { 5 } { 2 } x - \frac { 5 } { 2 } , y \right) \mid y \right.$ is any real number
C) $\{ ( - 9 , - 5 ) \}$
D){}

Quizplus · Accepted Answer

The system of equations is consistent and dependent, meaning it has infinitely many solutions. The second equation is a multiple of the first, indicating that both equations represent the same line. Therefore, the solution set involves a parameter (in this case, $y$), indicating that for any value of $y$, there's a corresponding $x$ value that satisfies both equations.

Solve the System Using Gaussian Elimination or Gauss-Jordan Elimination −6x+15y=152x−5y=−5\begin{array} { l } - 6 x + 15 y = 15 \\2 x - 5 y = - 5\end{array}−6x+15y=152x−5y=−5​

Solve the System Using Gaussian Elimination or Gauss-Jordan Elimination $\begin{array} { l } - 6 x + 15 y = 15 \\2 x - 5 y = - 5\end{array}$