Solve the problem.
-A parabolic mirror on a telescope 30 cm in diameter has a focal length of 15 cm. For the coordinate system shown, write an equation of the parabolic cross section of the mirror.
A) $y ^ { 2 } = 60 x$ for $- 15 \leq y \leq 15$
B) $x ^ { 2 } = 60 y$ for $- 15 \leq x \leq 15$
C) $y ^ { 2 } = 15 x$ for $- 15 \leq y \leq 15$
D) $y ^ { 2 } = 60 x$ for $- 30 \leq y \leq 30$

Question

Solve the problem.
-A parabolic mirror on a telescope 30 cm in diameter has a focal length of 15 cm. For the coordinate system shown, write an equation of the parabolic cross section of the mirror.  
A) $y ^ { 2 } = 60 x$ for $- 15 \leq y \leq 15$ 
B) $x ^ { 2 } = 60 y$ for $- 15 \leq x \leq 15$ 
C) $y ^ { 2 } = 15 x$ for $- 15 \leq y \leq 15$ 
D) $y ^ { 2 } = 60 x$ for $- 30 \leq y \leq 30$

Quizplus · Accepted Answer

The Answer of Solve the problem.
-A parabolic mirror on a telescope 30 cm in diameter has a focal length of 15 cm. For the coordinate system shown, write an equation of the parabolic cross section of the mirror.  
A) $y ^ { 2 } = 60 x$ for $- 15 \leq y \leq 15$ 
B) $x ^ { 2 } = 60 y$ for $- 15 \leq x \leq 15$ 
C) $y ^ { 2 } = 15 x$ for $- 15 \leq y \leq 15$ 
D) $y ^ { 2 } = 60 x$ for $- 30 \leq y \leq 30$

Solve the Problem y2=60xy ^ { 2 } = 60 xy2=60x

Solve the Problem $y ^ { 2 } = 60 x$