Determine the eccentricity of the hyperbola.
-$$\frac { ( x - 4 ) ^ { 2 } } { 144 } - \frac { ( y + 2 ) ^ { 2 } } { 25 } = 1$$
A) $e = \frac { 13 } { 5 }$
B) $e = 2$
C) $e = \frac { 12 } { 5 }$
D) $e = \frac { 13 } { 12 }$

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The Answer of Determine the eccentricity of the hyperbola.
-$$\frac { ( x - 4 ) ^ { 2 } } { 144 } - \frac { ( y + 2 ) ^ { 2 } } { 25 } = 1$$
A) $e = \frac { 13 } { 5 }$
B) $e = 2$
C) $e = \frac { 12 } { 5 }$
D) $e = \frac { 13 } { 12 }$

Determine the Eccentricity of the Hyperbola (x−4)2144−(y+2)225=1\frac { ( x - 4 ) ^ { 2 } } { 144 } - \frac { ( y + 2 ) ^ { 2 } } { 25 } = 1144(x−4)2​−25(y+2)2​=1

Determine the Eccentricity of the Hyperbola $\frac { ( x - 4 ) ^ { 2 } } { 144 } - \frac { ( y + 2 ) ^ { 2 } } { 25 } = 1$