Find the sum.
-Find the sum of the first 36 terms of the sequence. $\{ 1,8,15,22,29 , \ldots \}$
A) 4,572
B) 9,144
C) 4,446
D) 9,108

Question

Quizplus · Accepted Answer

This sequence is an arithmetic sequence where the first term $a_1 = 1$ and the common difference $d = 8 - 1 = 7$. The sum of the first $n$ terms of an arithmetic sequence is given by $S_n = \frac{n}{2}[2a_1 + (n-1)d]$. Substituting $n = 36$, $a_1 = 1$, and $d = 7$, we get $S_{36} = \frac{36}{2}[2*1 + (36-1)*7] = 18[2 + 35*7] = 18[2 + 245] = 18*247 = 4446$.

Find the Sum {1,8,15,22,29,…}\{ 1,8,15,22,29 , \ldots \}{1,8,15,22,29,…} A) 4,572 B) 9,144 C) 4,446 D) 9,108

Find the Sum $\{ 1,8,15,22,29 , \ldots \}$ A) 4,572
B) 9,144
C) 4,446
D) 9,108