Find the nth term $a _ { n }$ of a sequence whose first four terms are given.
-$$- \frac { 6 } { 12 } , - \frac { 7 } { 24 } , - \frac { 8 } { 36 } , - \frac { 9 } { 48 } , \ldots$$
A) $a _ { n } = \frac { n - 7 } { 12 n }$
B) $a _ { n } = \frac { n + 5 } { 12 n }$
C) $a _ { n } = - \frac { n + 5 } { 12 n }$
D) $a _ { n } = \frac { 7 - n } { 12 n }$

Question

Quizplus · Accepted Answer

The sequence can be expressed as $a_n = -\frac{n+5}{12n}$ because the numerator starts at -6 and decreases by 1 with each term (hence the $n+5$ part, since -6 + 5 = -1, and we subtract 1 more for each subsequent term), and the denominator starts at 12 and increases by 12n (hence the $12n$ part). This pattern matches the sequence given.

Find the Nth Term ana _ { n }an​ Of a Sequence Whose First Four Terms Are Given

Find the Nth Term $a _ { n }$ Of a Sequence Whose First Four Terms Are Given