Here is a sample proof that contains an error. Explain why the proof is not correct. Theorem: If $a \mid b$ and $b \mid c$, then $a \mid c$. Proof: Since $a \mid b , b = a k$.
Since $b \mid c , c = b k$.
Therefore $c = b k = ( a k ) k = a k ^ { 2 }$.
Therefore $a \mid c$.

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The Answer of Here is a sample proof that contains an error. Explain why the proof is not correct. Theorem: If $a \mid b$ and $b \mid c$, then $a \mid c$. Proof: Since $a \mid b , b = a k$.
Since $b \mid c , c = b k$.
Therefore $c = b k = ( a k ) k = a k ^ { 2 }$.
Therefore $a \mid c$.

Here Is a Sample Proof That Contains an Error a∣ba \mid ba∣b

Here Is a Sample Proof That Contains an Error $a \mid b$