Simplify. Assume that variables in the exponent represent nonzero integers and that all other variables are not 0.
-$\frac { x ^ { 6 a } \left( x ^ { 6 a } \right) ^ { 7 } } { x }$
A) $x ^ { 48 a - 1 }$
B) $x ^ { 51 a - 1 }$
C) $\frac { 1 } { 48 a - 1 }$
D) $x ^ { 36 a + 1 }$

Question

Quizplus · Accepted Answer

Using the rules of exponents, we first simplify the numerator: $x^{6a} \cdot (x^{6a})^7 = x^{6a} \cdot x^{42a} = x^{48a}$. Then, dividing by $x$ (which is $x^1$) gives $x^{48a-1}$.

Simplify Assume That Variables in the Exponent Represent Nonzero Integers x6a(x6a)7x\frac { x ^ { 6 a } \left( x ^ { 6 a } \right) ^ { 7 } } { x }xx6a(x6a)7​

Simplify Assume That Variables in the Exponent Represent Nonzero Integers $\frac { x ^ { 6 a } \left( x ^ { 6 a } \right) ^ { 7 } } { x }$