Solved

The Graph of the Equation Is a Circle $x^{2}+y^{2}=36$ A) Center $( 0,0 )$

Question 2

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x^{2}+y^{2}=36$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}=36 A) center ( 0,0 ) ; radius = 6 B) center ( 0,0 ) ; radius = \sqrt { 6 }$

A) center $( 0,0 )$ ; radius $= 6$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}=36 A) center ( 0,0 ) ; radius = 6 B) center ( 0,0 ) ; radius = \sqrt { 6 }$

B) center $( 0,0 ) ;$ radius $= \sqrt { 6 }$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}=36 A) center ( 0,0 ) ; radius = 6 B) center ( 0,0 ) ; radius = \sqrt { 6 }$