Solve the Compound Inequality $\frac { 4 } { 5 } x + 1 \leq 0 \text { or } - 3 x < - 12$

Solve the compound inequality. Give the answer in interval notation.
- $\frac { 4 } { 5 } x + 1 \leq 0 \text { or } - 3 x < - 12$

A) $( - \infty , 4 )$
B) $\left( - \infty , \frac { 5 } { 4 } \right] \cup ( 4 , \infty )$
C) $\left( - \infty , \frac { 4 } { 5 } \right] \cup ( - 9 , \infty )$
D) $\left[ \frac { 5 } { 4 } , 4 \right)$