Solve the system of equations.
-$$\left\{ \begin{array} { l }
\frac { x } { 3 } + \frac { y } { 9 } = 1 \
\frac { x } { 2 } - \frac { y } { 6 } = 0
\end{array} \right.$$
A) $\left( \frac { 3 } { 2 } , \frac { 9 } { 2 } \right)$
B) $\left( \frac { 9 } { 2 } , \frac { 3 } { 2 } \right)$
C) $\left\{ ( x , y ) \mid \frac { x } { 3 } + \frac { y } { 9 } = 1 \right\}$
D) $\varnothing$

Question

Solve the system of equations.
-$$\left\{ \begin{array} { l } 
\frac { x } { 3 } + \frac { y } { 9 } = 1 \
\frac { x } { 2 } - \frac { y } { 6 } = 0
\end{array} \right.$$
A) $\left( \frac { 3 } { 2 } , \frac { 9 } { 2 } \right)$
B) $\left( \frac { 9 } { 2 } , \frac { 3 } { 2 } \right)$
C) $\left\{ ( x , y ) \mid \frac { x } { 3 } + \frac { y } { 9 } = 1 \right\}$
D) $\varnothing$

Quizplus · Accepted Answer

By solving the system of equations, we find that $ x = \frac{3}{2} $ and $ y = \frac{9}{2} $.

Solve the System of Equations {x3+y9=1x2−y6=0\left\{ \begin{array} { l } \frac { x } { 3 } + \frac { y } { 9 } = 1 \\\frac { x } { 2 } - \frac { y } { 6 } = 0\end{array} \right.{3x​+9y​=12x​−6y​=0​

Solve the System of Equations $\left\{ \begin{array} { l } \frac { x } { 3 } + \frac { y } { 9 } = 1 \\\frac { x } { 2 } - \frac { y } { 6 } = 0\end{array} \right.$