Factor the polynomial completely.
-$$x ^ { 2 } + 6 x - 16$$
A) $( x - 8 ) ( x - 2 )$
B) $( x - 8 ) ( x + 1 )$
C) prime polynomial
D) $( x + 8 ) ( x - 2 )$

Name: Factor the polynomial completely. -\[x ^ { 2 } + 6 x - 16\] A) $( x - 8 ) ( x - 2 )$ B) $( x - 8 ) ( x + 1 )$ C) prime polynomial D) $( x + 8 ) ( x - 2 )$
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Question

Quizplus · Accepted Answer

The correct factorization is found by looking for two numbers that multiply to -16 and add to 6. Those numbers are 8 and -2, leading to the factors $(x + 8)$ and $(x - 2)$.

Factor the Polynomial Completely x2+6x−16x ^ { 2 } + 6 x - 16x2+6x−16

Factor the Polynomial Completely $x ^ { 2 } + 6 x - 16$