Factor.
-$$x ^ { 3 } y ^ { 2 } + 512 y ^ { 2 }$$
A) $y ^ { 2 } ( x - 8 ) \left( x ^ { 2 } + 8 x + 64 \right)$
B) $y ^ { 2 } ( x + 8 ) \left( x ^ { 2 } + 64 \right)$
C) $y ^ { 2 } ( x + 8 ) \left( x ^ { 2 } - 8 x + 64 \right)$
D) $( x y + 8 ) \left( x ^ { 2 } y ^ { 2 } - 8 x + 64 \right)$

Question

Quizplus · Accepted Answer

The expression can be factored as a sum of cubes: $x^3 + 512 = (x + 8)(x^2 - 8x + 64)$. Factoring out $y^2$ gives $y^2(x + 8)(x^2 - 8x + 64)$.

Factor - x3y2+512y2x ^ { 3 } y ^ { 2 } + 512 y ^ { 2 }x3y2+512y2

Factor
- $x ^ { 3 } y ^ { 2 } + 512 y ^ { 2 }$