Factor.
-$$81 x ^ { 2 } - 18 x + 1$$
A) $( x - 9 ) ^ { 2 }$
B) $( 9 x + 1 ) ( 9 x - 1 )$
C) $( 9 x - 1 ) ^ { 2 }$
D) Prime

Name: Factor. -\[81 x ^ { 2 } - 18 x + 1\] A) $( x - 9 ) ^ { 2 }$ B) $( 9 x + 1 ) ( 9 x - 1 )$ C) $( 9 x - 1 ) ^ { 2 }$ D) Prime
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Question

Quizplus · Accepted Answer

This is a perfect square trinomial. The square root of $81x^2$ is $9x$, and the square root of $1$ is $1$. Since the middle term is $-18x$, which is $2 \times 9x \times -1$, the expression factors as $(9x - 1)^2$.

Factor - 81x2−18x+181 x ^ { 2 } - 18 x + 181x2−18x+1

Factor
- $81 x ^ { 2 } - 18 x + 1$