Multiply.
-$$[ 4 x + ( 2 y - 1 ) ] ^ { 2 }$$
A) $16 x ^ { 2 } - 8 x y + 1$
B) $16 x ^ { 2 } + 16 x y - 8 x + 4 y ^ { 2 } - 4 y + 1$
C) $16 x ^ { 2 } + 4 y ^ { 2 } + 1$
D) $16 x ^ { 2 } - 16 x y + 1$

Question

Quizplus · Accepted Answer

To solve $[4x + (2y - 1)]^2$, we apply the formula $(a + b)^2 = a^2 + 2ab + b^2$, where $a = 4x$ and $b = 2y - 1$. Squaring each and applying the distributive property gives $16x^2 + 2(4x)(2y - 1) + (2y - 1)^2$, which simplifies to $16x^2 + 16xy - 8x + 4y^2 - 4y + 1$.

Multiply - [4x+(2y−1)]2[ 4 x + ( 2 y - 1 ) ] ^ { 2 }[4x+(2y−1)]2

Multiply
- $[ 4 x + ( 2 y - 1 ) ] ^ { 2 }$