Solve.
-Two bicyclists, one averaging $10 \mathrm { mph }$ and one averaging $16 \mathrm { mph }$, start from the same point. The slower bicyclist arrives at the end of the course a half-hour after the other bicyclist. Find the distance of the ride. Round to the nearest whole mile.
A) $21 \mathrm { mi }$
B) $8 \mathrm { mi }$
C) $13 \mathrm { mi }$
D) $\frac { 5 } { 6 } \mathrm { mi }$

Question

Quizplus · Accepted Answer

Let the distance be $d$. The time taken by the slower bicyclist is $\frac{d}{10}$ hours, and the time taken by the faster bicyclist is $\frac{d}{16}$ hours. The slower bicyclist takes a half-hour longer, so $\frac{d}{10} = \frac{d}{16} + 0.5$. Solving this equation gives $d = 13$ miles.

Solve -Two Bicyclists, One Averaging 10mph10 \mathrm { mph }10mph And One Averaging

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-Two Bicyclists, One Averaging $10 \mathrm { mph }$ And One Averaging