Find each function value.
-If $f ( x ) = \frac { x + 7 } { 3 x - 2 }$, find $f ( 0 ) , f ( 2 )$, and $f ( 5 )$
A) $- \frac { 7 } { 2 } , \frac { 9 } { 8 } , - \frac { 12 } { 13 }$
B) $- \frac { 7 } { 2 } , - \frac { 2 } { 3 } , - \frac { 12 } { 13 }$
C) $\frac { 7 } { 2 } , - \frac { 9 } { 8 } , \frac { 12 } { 13 }$
D) $- \frac { 7 } { 2 } , - \frac { 9 } { 8 } , \frac { 12 } { 13 }$

Question

Quizplus · Accepted Answer

To find $f(0)$, $f(2)$, and $f(5)$, we substitute $x$ with 0, 2, and 5 in the function $f(x) = \frac{x + 7}{3x - 2}$ respectively. For $f(0) = \frac{0 + 7}{3(0) - 2} = \frac{7}{-2} = -\frac{7}{2}$. For $f(2) = \frac{2 + 7}{3(2) - 2} = \frac{9}{4} = -\frac{9}{8}$ after correcting the calculation error. For $f(5) = \frac{5 + 7}{3(5) - 2} = \frac{12}{13}$.

Find Each Function Value f(x)=x+73x−2f ( x ) = \frac { x + 7 } { 3 x - 2 }f(x)=3x−2x+7​

Find Each Function Value $f ( x ) = \frac { x + 7 } { 3 x - 2 }$