Solve the inequality. Write the solution set in interval notation.
-$$\frac { 3 x - 21 } { x ^ { 2 } - 1 } \geq 0$$
A) $[ - 1,1 ] \cup [ 7 , \infty )$
B) $( - 1,1 ) \cup [ 7 , \infty )$
C) $( \infty , 1 ) \cup [ 7 , \infty )$
D) $( - 1,7 ]$

Question

Quizplus · Accepted Answer

First, factor the numerator and denominator: $\frac{3(x-7)}{(x+1)(x-1)} \geq 0$. The critical points are $x = -1, 1, 7$. Test intervals around these points to determine the sign of the expression. The solution set includes intervals where the expression is positive or zero. The correct interval notation is $( - 1,1 ) \cup [ 7 , \infty )$, where the inequality is non-negative.

Solve the Inequality 3x−21x2−1≥0\frac { 3 x - 21 } { x ^ { 2 } - 1 } \geq 0x2−13x−21​≥0

Solve the Inequality $\frac { 3 x - 21 } { x ^ { 2 } - 1 } \geq 0$