Solve the equation.
-$$y ^ { 2 } - 3 y = 2$$
A) $\varnothing$
B) $\left\{ \frac { 3 + i \sqrt { 17 } } { 2 } , \frac { 3 - i \sqrt { 17 } } { 2 } \right\}$
C) $\left\{ \frac { 3 + \sqrt { 17 } } { 2 } , \frac { 3 - \sqrt { 17 } } { 2 } \right\}$
D) $\left\{ \frac { - 3 + \sqrt { 17 } } { 2 } , \frac { - 3 - \sqrt { 17 } } { 2 } \right\}$

Question

Quizplus · Accepted Answer

The equation can be solved using the quadratic formula: $y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. Here, $a = 1$, $b = -3$, and $c = -2$. Solving gives real roots $\frac{3 \pm \sqrt{17}}{2}$.

Solve the Equation y2−3y=2y ^ { 2 } - 3 y = 2y2−3y=2

Solve the Equation $y ^ { 2 } - 3 y = 2$