Solve the equation.
-$2 x ^ { 2 } - 7 x = 9$
A) $\left\{ \frac { 9 } { 2 } , 1 \right\}$
B) $\left\{ \frac { 2 } { 9 } , - 1 \right\}$
C) $\left\{ \frac { 2 } { 9 } , 1 \right\}$
D) $\left\{ \frac { 9 } { 2 } , - 1 \right\}$

Question

Quizplus · Accepted Answer

First, rearrange the equation to standard form: $2x^2 - 7x - 9 = 0$. Using the quadratic formula, $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 2$, $b = -7$, and $c = -9$, we find the solutions to be $x = \frac{9}{2}$ and $x = -1$.

Solve the Equation 2x2−7x=92 x ^ { 2 } - 7 x = 92x2−7x=9

Solve the Equation $2 x ^ { 2 } - 7 x = 9$