Solve
-The Base of a Triangle Is 8 More Than $4 + \sqrt { 74 } \mathrm {~cm}$

Solve.
-The base of a triangle is 8 more than twice its height. If the area of the triangle is 70 square centimeters, find its base and height.

A) height: $4 + \sqrt { 74 } \mathrm {~cm}$
base: $- 2 + \sqrt { 74 } \mathrm {~cm}$
B) height: $- 2 + \sqrt { 74 } \mathrm {~cm}$
base: $4 + \sqrt { 74 } \mathrm {~cm}$
C) height: $- 2 + \sqrt { 74 } \mathrm {~cm}$
base: $4 + 2 \sqrt { 74 } \mathrm {~cm}$
D) height: $4 + 2 \sqrt { 74 } \mathrm {~cm}$
base: $- 2 + \sqrt { 74 } \mathrm {~cm}$