Solve.
-A ball is thrown downward with an initial velocity of 28 meters per second from a cliff that is 110 meters high. The height of the ball is given by the quadratic equation $h = - 4.9 t ^ { 2 } - 28 t + 110$ where $h$ is in meters and $t$ is the time in seconds since the ball was thrown. Find the time it takes the ball to hit the ground. Round your answer to the nearest tenth of a second.
A) $2.6$ seconds
B) $2.8$ seconds
C) $3.7$ seconds
D) $2.7$ seconds

Question

Quizplus · Accepted Answer

To find the time it takes for the ball to hit the ground, we need to solve the equation for $h = 0$. Setting the given quadratic equation to zero gives us $0 = -4.9t^2 - 28t + 110$. Solving this quadratic equation for $t$ (using the quadratic formula or any other method), we find that the positive root that makes physical sense for this scenario (time cannot be negative) is approximately $2.7$ seconds.

Solve -A Ball Is Thrown Downward with an Initial Velocity h=−4.9t2−28t+110h = - 4.9 t ^ { 2 } - 28 t + 110h=−4.9t2−28t+110

Solve
-A Ball Is Thrown Downward with an Initial Velocity $h = - 4.9 t ^ { 2 } - 28 t + 110$