Use the quadratic formula to solve the equation.
-$$4 x ^ { 2 } + 10 x = - 3$$
A) $\left\{ \frac { - 5 - \sqrt { 13 } } { 8 } , \frac { - 5 + \sqrt { 13 } } { 8 } \right\}$
B) $\left\{ \frac { - 10 - \sqrt { 13 } } { 4 } , \frac { - 10 + \sqrt { 13 } } { 4 } \right\}$
C) $\left\{ \frac { - 5 - \sqrt { 37 } } { 4 } , \frac { - 5 + \sqrt { 37 } } { 4 } \right\}$
D) $\left\{ \frac { - 5 - \sqrt { 13 } } { 4 } , \frac { - 5 + \sqrt { 13 } } { 4 } \right\}$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $4x^2 + 10x + 3 = 0$. Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 4$, $b = 10$, and $c = 3$, we find the solutions are $\frac{-10 \pm \sqrt{100 - 48}}{8} = \frac{-10 \pm \sqrt{52}}{8} = \frac{-10 \pm 2\sqrt{13}}{8} = \frac{-5 \pm \sqrt{13}}{4}$.

Use the Quadratic Formula to Solve the Equation 4x2+10x=−34 x ^ { 2 } + 10 x = - 34x2+10x=−3

Use the Quadratic Formula to Solve the Equation $4 x ^ { 2 } + 10 x = - 3$