Find the inverse of the one-to-one function.
-$$f ( x ) = \frac { 8 x + 5 } { 7 }$$
A) $f ^ { - 1 } ( x ) = \frac { 7 } { 8 x + 5 }$
B) $f ^ { - 1 } ( x ) = \frac { 7 x - 5 } { 8 }$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 7 \mathrm { x } + 5 } { 8 }$
D) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 7 } { 8 x - 5 }$

Question

Quizplus · Accepted Answer

To find the inverse function, swap $x$ and $y$ and solve for $y$. Starting with $y = \frac{8x + 5}{7}$, swap to get $x = \frac{8y + 5}{7}$, then solve for $y$ to get $y = \frac{7x - 5}{8}$.

Find the Inverse of the One-To-One Function f(x)=8x+57f ( x ) = \frac { 8 x + 5 } { 7 }f(x)=78x+5​

Find the Inverse of the One-To-One Function $f ( x ) = \frac { 8 x + 5 } { 7 }$