For the given one-to-one function f, find the following.
-$$f ( x ) = \sqrt { 6 x - 5 } - 5$$
Find $f ( 5 )$ and $f ^ { - 1 } ( 0 )$.
A) $f ( 5 ) = 25 ; f ^ { - 1 } ( 0 ) = 5$
B) $\mathrm { f } ( 5 ) = \frac { 25 } { 6 } ; \mathrm { f } ^ { - 1 } ( 0 ) = 0$
C) $\mathrm { f } ( 5 ) = 0 ; \mathrm { f } ^ { - 1 } ( 0 ) = 5$
D) $f ( 5 ) = 5 ; f ^ { - 1 } ( 0 ) = 0$

Question

Quizplus · Accepted Answer

To find $f(5)$, substitute $x = 5$ into the function: $f(5) = \sqrt{6(5) - 5} - 5 = \sqrt{30 - 5} - 5 = \sqrt{25} - 5 = 5 - 5 = 0$. To find $f^{-1}(0)$, set the function equal to 0 and solve for $x$: $0 = \sqrt{6x - 5} - 5$, which leads to $x = 5$ after solving the equation.

For the Given One-To-One Function F, Find the Following f(x)=6x−5−5f ( x ) = \sqrt { 6 x - 5 } - 5f(x)=6x−5​−5

For the Given One-To-One Function F, Find the Following $f ( x ) = \sqrt { 6 x - 5 } - 5$