Let E be the event that a corn crop has an infestation of ear worms, and let B be the event that a corn crop has an infestation of corn borers.Suppose that $P ( E ) = 0.18 , P ( B ) = 0.18$, and $P ( E$ and $B ) = 0.12$. Find the probability that a corn crop has either an ear worm infestation, a corn borer infestation, or both
A) $0.12$
B) $0.48$
C) $0.64$
D) $0.24$

Question

Quizplus · Accepted Answer

The probability of either event E or B or both occurring is given by the formula $P(E \cup B) = P(E) + P(B) - P(E \cap B)$. Substituting the given values: $0.18 + 0.18 - 0.12 = 0.24$.

Let E Be the Event That a Corn Crop Has P(E)=0.18,P(B)=0.18P ( E ) = 0.18 , P ( B ) = 0.18P(E)=0.18,P(B)=0.18

Let E Be the Event That a Corn Crop Has $P ( E ) = 0.18 , P ( B ) = 0.18$