Determine whether the table represents a discrete probability distribution.
$\begin{array} { c c }
\hline x & P ( x ) \
\hline - 4 & 0.3 \
- 3 & 0.15 \
- 2 & 0.1 \
- 1 & 0.5 \
\hline
\end{array}$

Question

Determine whether the table represents a discrete probability distribution. 
$\begin{array} { c c } 
\hline x & P ( x ) \
\hline - 4 & 0.3 \
- 3 & 0.15 \
- 2 & 0.1 \
- 1 & 0.5 \
\hline
\end{array}$

Quizplus · Accepted Answer

The sum of the probabilities exceeds 1 (0.3 + 0.15 + 0.1 + 0.5 = 1.05), which violates the requirement for a probability distribution where the total probability must equal 1.

Determine Whether the Table Represents a Discrete Probability Distribution xP(x)−40.3−30.15−20.1−10.5\begin{array} { c c } \hline x & P ( x ) \\\hline - 4 & 0.3 \\- 3 & 0.15 \\- 2 & 0.1 \\- 1 & 0.5 \\\hline\end{array}x−4−3−2−1​P(x)0.30.150.10.5​​

Determine Whether the Table Represents a Discrete Probability Distribution $\begin{array} { c c } \hline x & P ( x ) \\\hline - 4 & 0.3 \\- 3 & 0.15 \\- 2 & 0.1 \\- 1 & 0.5 \\\hline\end{array}$