$\begin{aligned}
x+2 y-3 z &=19 \
2 x-3 y+4 z &=-17 \
3 x-y &=4
\end{aligned}$
equations as a matrix equation AX=B is $\left[\begin{array}{rrr}
1 & 2 & -3 \
2 & -3 & 4 \
3 & -1 & 0
\end{array}\right]\left[\begin{array}{l}
y \
x \
z
\end{array}\right]=\left[\begin{array}{r}
19 \
-17 \
4
\end{array}\right]$
-Use an inverse matrix to solve the system given in above.

Question

$\begin{aligned}
x+2 y-3 z &=19 \
2 x-3 y+4 z &=-17 \
3 x-y &=4
\end{aligned}$
equations as a matrix equation  AX=B is $\left[\begin{array}{rrr}
1 & 2 & -3 \
2 & -3 & 4 \
3 & -1 & 0
\end{array}\right]\left[\begin{array}{l}
y \
x \
z
\end{array}\right]=\left[\begin{array}{r}
19 \
-17 \
4
\end{array}\right]$
-Use an inverse matrix to solve the system given in above.

Quizplus · Accepted Answer

The Answer of $\begin{aligned}
x+2 y-3 z &=19 \
2 x-3 y+4 z &=-17 \
3 x-y &=4
\end{aligned}$
equations as a matrix equation  AX=B is $\left[\begin{array}{rrr}
1 & 2 & -3 \
2 & -3 & 4 \
3 & -1 & 0
\end{array}\right]\left[\begin{array}{l}
y \
x \
z
\end{array}\right]=\left[\begin{array}{r}
19 \
-17 \
4
\end{array}\right]$
-Use an inverse matrix to solve the system given in above.

x+2y−3z=192x−3y+4z=−173x−y=4\begin{aligned}x+2 y-3 z &=19 \\2 x-3 y+4 z &=-17 \\3 x-y &=4\end{aligned}x+2y−3z2x−3y+4z3x−y​=19=−17=4​

$\begin{aligned}x+2 y-3 z &=19 \\2 x-3 y+4 z &=-17 \\3 x-y &=4\end{aligned}$